if tanx=5/12 find cosec=x
Answers
Answered by
3
if tanx =5/12
it means p/b = 5/12
so
b=12
and p=5
by pythagoras theorem
h^2=5^2+12^2
h^2 =25+144
h^2 = 169
h=13
cosec X = h/p
cosec X = 13/5
answer
it means p/b = 5/12
so
b=12
and p=5
by pythagoras theorem
h^2=5^2+12^2
h^2 =25+144
h^2 = 169
h=13
cosec X = h/p
cosec X = 13/5
answer
Answered by
9
tan x = 5 / 12 = perpendicular / base
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Find Hypotenuse :
_______________________________
by Pythagoras theorem , we get
(hypotenuse)^2
=( base)^2 + ( perpendicular)^2
(hypotenuse)^2 = ( 12 )^2 + ( 5 ) ^2
( hypotenuse )^2 = 144 + 25 =169
hypotenuse = √169 = 13
therefore ,
since we know that ,
cosec x = hypotenuse / perpendicular
cosec x = 13 / 5
_______________________________
Your Answer : cosec x = 13 / 5
_______________________________
_______________________________
Find Hypotenuse :
_______________________________
by Pythagoras theorem , we get
(hypotenuse)^2
=( base)^2 + ( perpendicular)^2
(hypotenuse)^2 = ( 12 )^2 + ( 5 ) ^2
( hypotenuse )^2 = 144 + 25 =169
hypotenuse = √169 = 13
therefore ,
since we know that ,
cosec x = hypotenuse / perpendicular
cosec x = 13 / 5
_______________________________
Your Answer : cosec x = 13 / 5
_______________________________
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