If tanx =m/m+1, tany= m/2m+1. Then find the value of x + y
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tan(a+b)=(tana+tanb)/1+tana.tanb
tan(x+y)=(tan x+tany)/1+tanx.tany
tan(x+y)=(m/m+1 + m/2m+1 )/1+m/m+1 . m/2m+1
x+y=taninverse(3m+2)m /3m.m +3m+1
tan(x+y)=(tan x+tany)/1+tanx.tany
tan(x+y)=(m/m+1 + m/2m+1 )/1+m/m+1 . m/2m+1
x+y=taninverse(3m+2)m /3m.m +3m+1
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