Physics, asked by rushikeshpose, 1 month ago

If temperature of 4 kg of material of specific heat capacity 300 J/kg C from 200C to 300C. Find heat

received​

Answers

Answered by nafiahkhan3
0

Answer:

Answer: The heat received by the material is 120 kJ.

Answered by sonalip1219
0

Given:-

mass of material, m=4 kg

specific heat capacity, C=300 J/kg-K

Temperature difference, \Delta{T}=300-200=100^{0}C

To Find:-

Heat received

Explanation:-

Since, temperature of material changes therefore, it is a case of specific heat addition in the material. The expression of specific heat is given by:-

Q=mC\Delta{T}

Substitute all the values in above equation.

\Rightarrow Q=4\times300\times100=120000J=120kJ

Therefore, 120 kJ of heat received to the material.

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