Question

If temperature of 4 kg of material of specific heat capacity 300 J/kg C from 200C to 300C. Find heat

received​

Answer 1

Answer:

Answer: The heat received by the material is 120 kJ.

Answer 2

Given:-

mass of material, m=4 kg

specific heat capacity, C=300 J/kg-K

Temperature difference, $\Delta{T}$=300-200=$100^{0}C$

To Find:-

Heat received

Explanation:-

Since, temperature of material changes therefore, it is a case of specific heat addition in the material. The expression of specific heat is given by:-

$Q=mC\Delta{T}$

Substitute all the values in above equation.

$\Rightarrow Q=4\times300\times100=120000J=120kJ$

Therefore, 120 kJ of heat received to the material.