Question

If temperatures of hot and cold reservoirs of a Carnot engine are respectively T1 and T2, engine will have 100% efficiency when (A) T2 = 273K (B) T1 = 273K (C) T2 = OK (D) T = OK​

Answer 1

Answer:

option (C) T₂ = 0 K

Explanation:

Given :

The temperatures of hot and cold reservoirs of a Carnot engine are respectively T₁ and T₂.

To find :

the condition when engine will have 100% efficiency

Solution :

The efficiency of a Carnot engine is given by,

 $\longmapsto \boxed{\bf \eta=1-\dfrac{T_2}{T_1}}$

where

T₁ is the temperature of the hot reservoir

T₂ is the temperature of the cold reservoir

The efficiency, η = 100%

$\longmapsto \sf 100 \%=1-\dfrac{T_2}{T_1} \\\\ \longmapsto \dfrac{100}{100}=1-\dfrac{T_2}{T_1} \\\\ \longmapsto 1=1-\dfrac{T_2}{T_1} \\\\ \longmapsto \dfrac{T_2}{T_1} =0 \\\\ \longmapsto T_2=0K$

Therefore, efficiency of Carnot engine is 100% when T₂ = 0 K