Question

If ten grams of water is decomposed, how many grams of hydrogen and oxygen will we get (hint: hydrogen and oxygen are present in a 1:8 ratio in water)?

Please explain the solution.

Answer 1

1.1g of hydrogen+8.9g of oxygen

Answer 2

Answer: 1.11 grams of $H_2$ and 8.88 grams of $O_2$ will be produced.

Explanation: Decomposition of water is written as:

$H_2O(l)\rightarrow H_2(g)+\frac{1}{2}O_2(g)$

Mass of $H_2O=18g$

Mass of $H_2=2g$

Mass of  $\frac{1}{2}O_2=16g$

By Stoichiometry, 18 grams of water produces 2 grams of hydrogen gas and 16 grams of  oxygen gas.

We are given, 10 grams of water, so

Mass of hydrogen gas produced = $\frac{2}{18}\times 10=1.11grams$

Mass of Oxygen gas produced = $\frac{16}{18}\times 10=8.88grams$

Mass ratio of Hydrogen and oxygen = 1.11 : 8.88

                                                             = 1 : 8