Question

In figure angle B = angle E , BD=CE and angle 1 = angle 2. Show that triangle ABC congruent to triangle AED

Answer 1

HERE IS YOUR PERFECT ANSWER:
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In ∆ABC and ∆AED,
angle B = angle E ( given )
angle 1 = angle 2 ( given )
Therefore,angle 1 + angle 3 = angle 2 + angle 3
(by adding angle 3 on both sides )
So, angle BAC = angle DAE
Also, BE = CE ( given )
Therefore, BD + CD = CE + CD ( by adding CD
on both sides )
So, BC = DC.

Therefore, ∆ABC is congruent to ∆AED
( by AAS ) .

HOPE THIS WILL HELP YOU.
PLEASE MARK IT AS THE BRAINLLIEST.
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Answer 2

given : <B = <E
BD = CE
<1 =<2
IN ∆ABC and ∆AED
= BD = CE (GIVEN) add both side DC
BD+DC = CE + DC
BC = DE
= <1 = <2
<1+<3 = <2+<3. [ adding equal both the side]
BAC = DAE
<B = <C
therefore,∆ABC ~ ∆AED [AAS - criteria]





thx hope this would help u ☺️☺️☺️☺️☺️☺️:D:):D