If ten years hence A's age be double the
B's age ten years back and now it is ten
years more than that of B's age. What is
the age of B ?
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Step-by-step explanation:
Let A age be x and B age be y
Ten year's hence : x+10, y+ 10
x+10 = 2 ( y+ 10 -10 )
x + 10 = 2( y )
x - 2y = -10 ===> eq 1
Present age :
x = 10 +y
x - y = 10 ===> eq 2
Elimination method
x - 2y = -10
x - y = 10 ( change sign and cancel x )
____________
- y = -20
y = 20
x - y = 10
x - 20 = 10
x = 10 + 20
x = 30
x = 30
A's age = 30 years
B's age = 20 years
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