If
![0 \leqslant x \leqslant 2\pi 0 \leqslant x \leqslant 2\pi](https://tex.z-dn.net/?f=0+%5Cleqslant+x+%5Cleqslant+2%5Cpi)
, then find the number of solutions of the equation sin 2x = cos 3x.
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Answered by
1
Answer:
If
0 \leqslant x \leqslant 2\pi0⩽x⩽2π
, then find the number of solutions of the equation sin 2x = cos 3x.
Answered by
0
Answer:
If
0 \leqslant x \leqslant 2\pi0⩽x⩽2π
, then find the number of solutions of the equation sin 2x = cos 3x.
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