Math, asked by khushikala2428, 7 hours ago

If
0 \leqslant x \leqslant 2\pi
, then find the number of solutions of the equation sin 2x = cos 3x.​

Answers

Answered by rajput2425688
1

Answer:

If

0 \leqslant x \leqslant 2\pi0⩽x⩽2π

, then find the number of solutions of the equation sin 2x = cos 3x.

Answered by krishnandjoshi411
0

Answer:

If

0 \leqslant x \leqslant 2\pi0⩽x⩽2π

, then find the number of solutions of the equation sin 2x = cos 3x.

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