Question

If $1\frac{1}{2}$ moles of oxygen combine with Al to form Al₂O₃ the weight of Al used in the reaction is (Al = 27)
(a) 27 g
(b) 54 g
(c) 49.5 g
(d) 31 g

Answer 1

Hello Friend

The answer of u r question is

OptionmB..

Thank you

Answer 2

${\huge {\mathfrak {Answer :-}}}$

➡️ Let the mole of Al combined be x.

So, x : 2 : : 1.5 : 3.

Or, x = 3/3 = 1.

1 mole of Al = 27.

➡️ Option (A) 27 g.

That's it..