If
and
then find value of
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Answer:
15x+17y=21 .....(1)
17x+15y=11 .....(2)
17×eqn(1)−15× eqn(2) gives
255x+289y−255x−225y=357−165
⇒64y=192
⇒y=64192=3
Substitute the value of y=3 in (1) we get
15x+17×3=21
⇒15x=21−51=−30
∴x=15−30=−2
Hence x=−2,y=3
And x+y=−2+3=1
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