Question

if
$({2.3})^{x } = ( {0.23})^{y} = 1000$
then find the value of 1/x - 1/y​

Answer 1

Answer:

226

Step-by-step explanation:

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Answer 2

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(2.3)^x = (0.23)^y = 1000 

=> log10(2.3)^x = log10(0.23)^y = log10(103)

=> x log10(2.3) = ylog10(0.23) = 3

=> 3/x = log10 2.3, 3/y = log10 0.23

=> 3(1/x - 1/y) = 1

=> 1/x - 1/y = 1/3