If
![{2}^{5x} \div {2}^{x} = \sqrt[5] {2}^{20}](https://tex.z-dn.net/?f=+%7B2%7D%5E%7B5x%7D++%5Cdiv++%7B2%7D%5E%7Bx%7D++%3D++%5Csqrt%5B5%5D+%7B2%7D%5E%7B20%7D+ "{2}^{5x} \div {2}^{x} = \sqrt[5] {2}^{20}")
find x.
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given
b is x here......
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