if
![2 + \sqrt[y]{3} = \frac{ \sqrt{3} - 1}{ \sqrt[2]{3} + 11 } 2 + \sqrt[y]{3} = \frac{ \sqrt{3} - 1}{ \sqrt[2]{3} + 11 }](https://tex.z-dn.net/?f=2+%2B++%5Csqrt%5By%5D%7B3%7D++%3D+%5Cfrac%7B+%5Csqrt%7B3%7D++-+1%7D%7B+%5Csqrt%5B2%5D%7B3%7D+%2B+11+%7D+)
then find y?
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happy teacher's Day sir please find the attached document for me and please only on devices you use to you a circle radius and India Pvt limited and its application of appropriate
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