Question

If $a^{3} + b^{3} +6abc = 8c^{3}$ then find the relation between a, b, c

Answer 1

a³+b³+6abc=8c³

a³+b³-8c³=-6abc

a³+b³-(2c)³=3.a.b.-2c

if a³+b³+c³=3abc

then a+b+c=0

hence

a+b-2c=0

a+b=2c