Math, asked by ysaisreenathrepbjx02, 11 months ago

If
a {x}^{2} + 2 {a}^{2} x + {b}^{3}
is divisible by x+a then which condition must be true,[a, b>0]
(A)
a + b = 0

(B)
 {a}^{2} + 2ab + {b}^{2} = 0
(C)
 {a}^{2} - ab + {b}^{2} = 0
(D)
a = b

Answers

Answered by Anonymous
1

Answer:


Option (A)

a=-b


According to question both a and b is greater than 0

(A) ××××××××

----------------------------------------------


(B) a^2 +2ab+b^2=0

(a+b)^2 =0


a+b= 0option A and option B are same

(B)×××××××××××××

__________________________


Option (C)

a^2-ab+b^2=0

(a+b)^2 -3ab=0


(a+b)=√(3ab)


(C)××××××××××

--------------------------------------------

Option (D)

a=b



ax^2 + 2a^2x +b^3


ax^2 +2a^2x +a^3


a( x^2 +2ax+a^2)


a×(x+a)^2


Option D satisfied the equation

So

Answer is option (D)



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