If

is divisible by x+a then which condition must be true,[a, b>0]
(A)

(B)

(C)

(D)
Answers
Answered by
1
Answer:
Option (A)
a=-b
According to question both a and b is greater than 0
(A) ××××××××
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(B) a^2 +2ab+b^2=0
(a+b)^2 =0
a+b= 0option A and option B are same
(B)×××××××××××××
__________________________
Option (C)
a^2-ab+b^2=0
(a+b)^2 -3ab=0
(a+b)=√(3ab)
(C)××××××××××
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Option (D)
a=b
ax^2 + 2a^2x +b^3
ax^2 +2a^2x +a^3
a( x^2 +2ax+a^2)
a×(x+a)^2
Option D satisfied the equation
So
Answer is option (D)
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