Question

if
$cos {}^{2}x - sin {}^{2}x = 1 \div 2$
then
$tan { }^{2}x =$
what it will be?
solve out the tan²x =?

Answer 1

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Answer 2

The answer is given below :

Given,

${cos}^{2} x - {sin}^{2} x = \frac{1}{2} \\ \\ or \: \: cos2x = cos60 \\ \\ or \: \: 2x = 60 \\ \\ so \: \: x = 30$

Now,

${tan}^{2} x \\ \\ = {tan}^{2} 30 \\ \\ = {(tan30)}^{2} \\ \\ = { (\frac{1}{ \sqrt{3} }) }^{2} \\ \\ = \frac{1}{ 3}$

Thank you for your question.