Question

If
$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } = a + b \sqrt{7}$
find values of "a" and "b"

Answer 1

Mark this answer as brainliest answer

Answer 2

Heya......!!!

By simple Rationalisation

$\frac{3 + \sqrt{7} }{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 + \sqrt{7} } \\ \frac{(3 + \sqrt{7} ) {}^{2} }{3 {}^{2} - \sqrt{7} {}^{2} } \\ \frac{9 + 7 + 6 \sqrt{7} }{9 - 7} \\ \frac{16 + 6 \sqrt{7} }{2} \\ \\ finlly \: it \: \: comes \: \: = > > 8 + 3 \sqrt{7}$
So Equating RHS to LHS

8+3√7. = a+b√7
Hence ,,

➡a = 8
➡b = 3


Hope it helps u ^_^