Question

If
$if \: x + y = 12 \\ \\and \: xy= 32 \\ \\ find \: x {}^{2} + y {}^{2}$
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Answer 1

Step-by-step explanation:

$x + y = 12 \\ xy = 32 \\ {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ {12}^{2} = {x}^{2} + {y}^{2} + 2 \times 32 \\144 - 64 = {x}^{2} + {y}^{2} \\ = 80$

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Answer 2

Answer:

x^2+y^2=80

Step-by-step explanation:

x+y=12

squaring on both sides

(x+y)^2=(12)^2

x^2+y^2+2xy=144

xy=32

=>x^2+y^2+2(32)=144

=>x^2+y^2=144-64

=>x^2+y^2=80

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