Question

If $\int\limits^{\alpha}_0 {4x^{3}} \, dx=16$; Find 'α'.

Answer 1

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Answer 2

Answer:

a=2

Step-by-step explanation:

To find the value of a,we must integrate the function then apply limits

so

$\int\limits^a_0 {4x^{3} } \, dx \\ \\ \\=[\frac{4x^{4} }{4} ]\limits^a___0$

$a^{4}-0^{4} =16\\ \\a^{4} =16\\ \\a^{4}=2^{4}$

after taking fourth root we get that

a=2