Question

if
$log_{7}(2)$
= m, then
$log_{49}(28)$
Is equal to

a) 2(1+2m)
b)1+2m/2
c)2/1+2m
d)1+m​

Answer 1

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

Answer 2

Heya!!

$log_{7}(2) = m \: \\ \\ find \: \: log_{49}(28) \\ \\ log_{49}(28) = log_{7 {}^{2} }(2 \times 14) \\ \\ log_{49}(28) = (1 \div 2) log_{7}(2 \times 14) \\ becoz \: \: log_{x {}^{n} }(y) = (1 \div n) log_{x}(y) \\ \\ log_{49}(28) = (1 \div 2) log_{7}(2) + (1 \div 2) log_{7}(14) \\ \\ log_{49}(28) = (1 \div 2)m + (1 \div 2) log_{7}(2 \times 7) \\ \\ log_{49}(28) = (1 \div 2)m + (1 \div 2)m + (1 \div 2) \\ becoz \: \: log_{ \alpha }( \alpha ) = 1 \\ \\ log_{49}(28) = (1 + 2m) \div 2$