Question

If
$log ( k^{2} -4k +5) = 0$
Find the value of 4k = ?

Answer 1

Heya User,

--> log ( k² - 4k + 5 ) = 0

Now, $log_ab = c=\ \textgreater \ a^c = b$
Similarly, k² - 4k + 5 = 10^0
=> k² - 4k + 5 = 1
=> k² - 4k + 4 = 0
=> [ k - 2 ]² = 0
=> k - 2 = 0
=> k = 2;

.'. 4k = 4*2 = 8;

Answer 2

Answer:

hi sir pls solve me this problem pls

Step-by-step explanation:

solve the equation 6(3x+2)+5(7x-6) -12x=5 (6x-1) + 6(x-3) and verify your answer.

pls sir !