If
![log_{ \sqrt{8} }(x) = 3 \times \frac{1}{3} log_{ \sqrt{8} }(x) = 3 \times \frac{1}{3}](https://tex.z-dn.net/?f=++log_%7B+%5Csqrt%7B8%7D+%7D%28x%29++%3D+3+%5Ctimes+%5Cfrac%7B1%7D%7B3%7D+)
then x= ?
Answers
Answered by
1
Answer:
log 8 x = 1/3 × 3
log 8 x = 1
log x = 1/8.
Similar questions
English,
6 months ago
Chemistry,
6 months ago
Computer Science,
1 year ago
English,
1 year ago
Math,
1 year ago