Question

If
$p (x) = {x}^{2} + x + 4x + 3$
Evaluate
$p(2) - p( - 1) + p( \frac{1}{2} )$

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Answer 1

Answer:

Let X,Y and Z be three independent random variables with X∼N(μ,σ2), and Y,Z∼Uniform(0,2). We also know that

E[X2Y+XYZ]=13,E[XY2+ZX2]=14.

Find μ and σ.

Step-by-step explanation:

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Answer 2

Given

P(x) = x^2 + x + 4x + 3

P(2)-P(-1)+P(1/2) =?

SOLUTION

P(x)

= x^2 + x + 4x + 3

= x^2 + 5x + 3

P(2) Put x = 2

= (2)^2 + 5(2) + 3

= 4 + 10 + 3

=17

P(2) = 17

P(-1) Put x = 17

= (-1)^2 + 5(-1) + 3

= 1 - 5 + 3

= - 1

P(-1) = - 1

P(1/2) Put x = 1/2

= (1/2)^2 + 5(1/2) + 3

= (1/4) + 5/2 + 3 (Take LCM)

= (1+10+12)/4

= 23/4

P(1/2) = 23/4

P(2)-P(-1)+P(1/2) = 17 - (-1) + 23/4

= 17 + 1 +23/4

= 18 + 23/4

= (72+23)/4

= 95/4

P(2)-P(-1)+P(1/2) = 95/4