Question

If $S_{n}=\sum \limits^{n}_{r=0}\ \frac{1}{^{n}C_{r}}\ and\ t_{n}=\sum \limits^{n}_{r=0}\ \frac{r}{^{n}C_{r}},\ then\ \frac{t_{n}}{S_{n}}$ is equal to
(a) $\frac{2n-1}{2}$
(b) $\frac{1}{2}n-1$
(c) n – 1
(d) $\frac{1}{2}n$

Answer 1

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