Question

If $\sf{(\frac{x}{3} + 1,y - \frac{2}{3}) = ( \frac{5}{3}, \frac{1}{3}) }$, find the values of x and y.
​

Answer 1

It is given that

$\sf{(\frac{x}{3} + 1,y - \frac{2}{3}) = ( \frac{5}{3}, \frac{1}{3}) }(3x+1,y−32)=(35,31)$

Since the ordered pairs are equal the corresponding element will also be equal

Therefore

$\frac{x}{3} + 1 =  \frac{5}{3} \: and \: y - \frac{2}{3} = \frac{1}{3}$

⇒y=1

⇒$\frac{x}{3} + 1 = \frac{5}{3}$

⇒x=2

∴x=2 and y=1

Answer 2

$\huge\color{pink}\boxed{\colorbox{Black}{❥ Answer}}$

Given ,

$( \frac{x}{3} + 1.y - \frac{2}{3}) = ( \frac{1}{5} . \frac{1}{3} (3x + 1.y - 32) - 3$

The element must be equal ,

So ,

$= \frac{x}{3} + 1 = \frac{5}{3} \\ = y - \frac{2}{3} = \frac{1}{3}$

Therefore y = 1

$\frac{x}{3} + 1 = \frac{5}{3}$

X = 2

So , The value of y = 1 and x = 2 .

Hope it will help you Blink