prove it please i need the answer .
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Step-by-step explanation:
ABC is a given triangle with, AB = AC.
To prove: Angle opposite to AB = Angle
opposite to AC (i.e) ZC ZB
Construction: Draw AD perpendicular to BC
.. ZADB = ZADC = 90°
Proof:
Consider AABD and AACD
AD is common
AB = AC
... ZADB = ZADC = 90°
Hence ZABD = ZACD
ZABC = ZACB
ZB = ZC. Hence the proof
This is known as Isosceles triangle theorem
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