If = 0, then
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= ?
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||✪✪ QUESTION ✪✪||
If x² - √7x - 1 = 0, Then Find x¹⁰ - 78x⁶ - 79x² = ?
|| ✰✰ ANSWER ✰✰ ||
➼ x² - √7x - 1 = 0
Taking x common,
➼ x(x - √7 - 1/x) = 0
➼ (x - 1/x) = √7
Squaring both sides and using (a - b)² = a² + b² - 2ab in LHS, we get,
➼ x² + 1/x² - 2 * x * 1/x = 7
➼ (x² + 1/x²) = 9 ------------- Equation ❶
Also, Taking LCM of Equation ❶ in LHS, we get,
➼ (x⁴ + 1)/x² = 9
➼ (x⁴ + 1) = 9x² -------------- Equation ❷
Also, Squaring both sides of Equation ❶ again, we get,
➻ (x² + 1/x²)² = 9²
➻ x⁴ + 1/x⁴ + 2*x²*1/x² = 81
➻ (x⁴ + 1/x⁴) = 79
➻ (x⁴ - 79) = (-1/x⁴) --------------- Equation ❸
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Now, we have to Find :-
☛ x¹⁰ - 78x⁶ - 79x²
☛ x¹⁰ + x⁶ - 79x⁶ - 79x²
☛ x⁶(x⁴ + 1) -79x²(x⁴ + 1)
☛ (x⁴ + 1)(x⁶ - 79x²)
☛ (x⁴ + 1) * x²(x⁴ - 79)
Putting values From Equation ❷ & ❸ now, we get,
☛ (9x²) * x² * (-1/x⁴)
☛ (-9x⁴) * (1/x⁴)
☛ (-9) (Ans.)
Hence, The value of (x¹⁰ - 78x⁶ - 79x²) will be (-9).
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☙❦⟪ Now, For One More Solution Refer To The image ..⟫❦☙
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