Question

If $sin^{-1} \bigg(\frac{2a}{1+a^2} \bigg) + cos^{-1} \bigg(\frac{1-a^2}{1+a^2} \bigg) = tan^{-1}\bigg(\frac{2x}{1-x^2} \bigg)$ , where a, x ∈ ]0, 1[ then find the value of x.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

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