Math, asked by chandan99916, 11 months ago

if
 \sqrt{33 }  = 5.643 \: then \: the \: value \: of \:  \sqrt{3 \div 11} is

Answers

Answered by TakenName
2

Answer:

0.513

Step-by-step explanation:

\sqrt{\frac{3}{11} }=\frac{\sqrt{3} }{\sqrt{11} }=\frac{\sqrt{33} }{11}

It is given that \sqrt{33}=5.643.

\frac{5.643}{11}=\frac{5643}{11000}=\frac{513}{1000} =0.513

0.513

Answered by slicergiza
0

The value of \dsqrt{3\div 11} is 0.513.

Step-by-step explanation:

Given problem,

\sqrt{3\div 11}

or

\sqrt{\frac{3}{11}}

=\frac{\sqrt{3}}{\sqrt{11}}

For rationalizing denominator,

Multiply both numerator and denominator by \sqrt{11},

=\frac{\sqrt{3}\times \sqrt{11}}{\sqrt{11}\times \sqrt{11}}

=\frac{\sqrt{33}}{11}

We have, √33 = 5.643,

=\frac{5.643}{11}

=0.513

Hence, the value of \sqrt{3\div 11} is 0.513.

Note: \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}, \sqrt{a}\times \sqrt{b}=\sqrt{ab}

#Learn more:

Solve the expressions :

https://brainly.in/question/10523870

https://brainly.in/question/12597352

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