Question

If
$\tan(a + b) = 1 \: and \: \tan(a - b) = 1 \div {3}^{2} . {0}^{0} < a + b < {90}^{0} .a > b \:$
then find the of A and B​

Answer 1

Here is your answer →

tan(A+B) = 1
tan(A-B) = 1
=> A+B =1 -(1)
A-B =1 -(2)
from equation 1 and 2 we get ;
A+B=1
A-B=1
2A=2
=> A= 1
PUT A=1 in equation (1)
We Get B = 0

Hope it helps you ♠

Answer 2

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