Question

If
$tan2a = \cot(a - 18)$
where 2a oa acute angle, find the value of a.....
Plz solve step by step...

Answer 1

Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️

tan2a = cot(a - 18)


As we know,

tanθ = Cot (90 - θ)


Cot(90 - 2a) = Cot(a - 18)

Removing Cot from both side


90 - 2a = a - 18

3a = 90 + 18

3a = 108

a = 108/3

a = 36

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$i \: hope \: it \: will \: help \: you$

Thank you ✌️☺️

Answer 2

Hey !!! ^_^

Here is your answer

⬇️⬇️⬇️⬇️⬇️⬇️

tan2a = cot(a - 18)

change tan to cot


Cot(90 - 2a) = Cot(a - 18)


90 - 2a = a - 18

3a = 90 + 18

3a = 108

a = 108/3

a = 36

_____________________

Thnq ☺️