Question

if $x = 3 + \sqrt{8}$then the value of$( {x}^{2} + 1 \div {x}^{2} )$is​

Answer 1

Answer:

Given that..

x=3+8–√…(1)

⇒1x=3−8√(3)2−(8√)2

⇒1x=3−8–√….(2)

Now adding (1) & (2) we get…

x+1x=(3+8–√)+(3−8–√)

⇒x+1x=6

Now,

x2+1x2

=(x+1x)2–2.x1x

=62–2

=36–2

=34 . (Ans).

Answer 2

→x 2 + x 2 1

hope it will help you