Question

If $x=\frac{-1}{2}$, is a solution of the quadratic equation 3x²+2kx-3=0, find the value of k.

Answer 1

SOLUTION  :

Given : 3x² + 2kx - 3 = 0

Since, x = - 1/2  is a solution of given equation, so it will satisfy the equation.

On putting x = -½  in given equation,

3x² + 2kx - 3 = 0

3(-1/2)² + 2k(-1/2) − 3 = 0

3 × ¼ - k - 3 = 0

¾ - k - 3 = 0

k = ¾ - 3  

k = (3 - 12)/4

k = - 9/4  

Hence, the value of k is - 9/4.

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Answer 2

Solution :

Substitute x = -1/2 in given

quadratic equation

3x² + 2kx - 3 = 0 , we get

' k ' value .

3(-1/2)² + 2k(-1/2) - 3 = 0

=> 3/4 - k - 3 = 0

=>- k = 3 - 3/4

=> -k = ( 12 - 3 )/4

=> -k = 9/4

=> k = -9/4

Therefore ,

k = -9/4

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