Question

If $(x+\frac{1}{3}, \ \frac{y}{2}-1)=(\frac{1}{2}, \ \frac{3}{2})$, find x and y.

Answer 1

$from \: the \: question \\ \: x + \frac{1}{3} = \frac{1}{2} and \: \frac{y}{2} - 1 = \frac{3}{2}$
Now we have to Solve the equations...
$x + \frac{1}{3} = \frac{1}{2} \\ = > x = \frac{1}{2} - \frac{1}{3} \\ = > x = \frac{3 - 2}{6} \\ = > x = \frac{1}{6}$

Similarly
$\frac{y}{2} - 1 = \frac{3}{2} \\ = > \frac{y}{2} = \frac{3}{2} + 1 \\ = > \frac{y}{2} = \frac{3 + 2}{2} \\ = > \frac{y}{2} = \frac{5}{2} \\ = > y = \frac{5}{2} \times 2 \\ = > y = 5$
So our answer is (1/6 , 5) = (x,y)
Final Answer
$x = \frac{1}{6} and \: y = 5$
I HOPE IT HELPS YOU...!!!

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