Question

If
$x + \frac{1}{x} = 3$
,then fixed the value of
$x {}^{2} + \frac{1}{x {}^{2} }$
​

Answer 1

$x + \frac{1}{x} = 3$

so,

$x ^{2} + \frac{1}{x^{2} }$

$(x + \frac{1}{x} ) ^{2} - 2 \times x \times \frac{1}{x}$

$(3) ^{2} - 2$

$9 - 2$

$7$