If 
then prove that dy/dx = xloga - y/ x logx
qais:
about term a??
abhii dekho glt likh diya tha :P
but what to prove....that terms equals to what???
lol again :P
question ka pic upload krdo na...better hoga
now fyn :P
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taking ㏒ both sides,
y㏒x = x㏒a
now differentiating both side with respect to x,
dy/dx(㏒x) +y/x = ㏒a
⇒dy/dx = (㏒a -y/x)/㏒x
=(x㏒a -y)/x㏒x
y㏒x = x㏒a
now differentiating both side with respect to x,
dy/dx(㏒x) +y/x = ㏒a
⇒dy/dx = (㏒a -y/x)/㏒x
=(x㏒a -y)/x㏒x
x ke with respect diff kiya
ni ...y ke respect me
oh haan x ke respect me
haan thanks :)
my pleasure
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