if the 10th term of an a.p. is 52 and the 16th term is 82, find the 32nd term and the general form
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goyalvikas78:
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Here is your solution
Given :-
a10=52
I. e
a+9d=52............ (1)
a16=82
I. e
a+15d=82................. (1)
subtract equation (i) from (ii)
a+15d-(a+9d)=82-52
=>15d-9d=30
=>6d=30
=>d=5
put d = 5 in (i)
a+9d=52
a+9(5)=52
a=52-45
a=7
a32=a+31d
a32=7+31(5)
a32=7+155=162
Hence,
32 term is 162
hope it helps you
Given :-
a10=52
I. e
a+9d=52............ (1)
a16=82
I. e
a+15d=82................. (1)
subtract equation (i) from (ii)
a+15d-(a+9d)=82-52
=>15d-9d=30
=>6d=30
=>d=5
put d = 5 in (i)
a+9d=52
a+9(5)=52
a=52-45
a=7
a32=a+31d
a32=7+31(5)
a32=7+155=162
Hence,
32 term is 162
hope it helps you
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