if the 12th term of an ap is -13 and the sum of the first four terms is 24 what is the sum of first 10 terms
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mote asibani
mote asibani
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a+(n-1)d=nth term
a+11d=-13 ........................(1st equation)
sum of n terms = n/2(2a+(n-1)d)
4/2(2a+3d)=24
4a+6d=24 ...................(2nd equation)
4a+6d=24
a+11d=-13 (multiply 4 on both sides)
4a+44d=52 .......................(3rd equation)
subtract 1 from 3
4a+44d=52
4a+6d=24
(44-6)d=28
38d=28
d=28/38
a+11d=-13
a+11(28/38)=-13
a=-13*38/11*28
a=1257
5(2514+9(28/38)
approxiamately 12,603
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