Question

if the 15th of an ap is 59 and 11th of the same ap is 43 then its 150th term is
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Answer 1

Step-by-step explanation:

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......here, 15th term = 59

T15 = 59

= a+14d = 59__________(equation 1st)

here, 11th term = 43

T11 = 43

a+10d = 43______equation (2nd)

.....here,

a = first term

d = common difference

$equation \: (1st) - eqution(2nd)$

a+14d—a—10d = 59—43

4d= 16

d = 16/4

d = 4

putting the value of d in equation 1.

a+14d = 59

a+14×4 = 59

a+56 = 59

a = 59—56

a = 3

then, 150th term of the AP.

T150= a+149d

.....3+149×4

= 3+596

= 599

....hence, the 150th term foof the AP is 599...

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