If the 15th term of an AP is 'x' and the 28th term is 'y'. Find the first term and common difference in x and y
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A(15) = a+14d = x
A(28) = a+27d = y
So , 13d = y-x
d = (y-x)/13
Common difference (d) = (y-x)/13
Now , a + 14/13*(y-x) = x
a = x - 14(y-x)/13
a = (13x-14y+14x)/13
first term (a) = (27x-14y)/13
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