Question

rationalising factor of 2 minus root 3 is​

Answer 1

Answer:2+root3

Step-by-step explanation:

Answer 2

Answer:

1

Step-by-step explanation:

R.F. of 2-$\sqrt{3$ is 2+$\sqrt{3$

So, (2-$\sqrt{3$)(2+$\sqrt{3$)            [ (a+b)(a-b) = $a^{2}$-$b^{2}$ ]

$2^{2}$ - $\sqrt{3^{2} }$

4 - 3

= 1