Question

if the 1729=1×A+7×B+2×C+9×D find the no of 1's in A+B+C+D​

Answer 1

Answer:

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Answer 2

Here: 1729 = 1000 + 700 + 20 + 9

or, 1729 = 1 × 1000 + 7 × 100 + 2 × 10 + 9 × 1 .. (1)

Given:

1729 = 1 × A + 7 × B + 2 × C + 9 × D ... (2)

Comparing (1) and (2), we get

A = 1000, B = 100, C = 10, D = 1

So, A + B + C + D = 1000 + 100 + 10 + 1

= 1111

Therefore there are four 1s in A + B + C + D.