Question

If the 17th term of an A.P. exceeds its 10th term by 7, find the common difference of the

A.P.
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Answer 1

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MARK BRAINLIEST.

Answer 2

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Ans. Let a be the first term and d the common difference .

It is given !

$a17- a10= 7$

$=> (a+16d) - (a+9d) =7$

$=> 7d = 7$

$=> d=1.$

Thus , the common difference is 7.

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