Question

if the 17th term of an ap is 1/9 and the 9th term is 1/7 . find the 63rd term .

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Answer 1

Suppose a be the first term and d be the common difference of an A.P.So seventh term = t 7 = a + 7 - 1 d = 1 9⇒ a + 6 d = 1 9 . . . . . . ( i )And 9th term = t 9 = a + 9 - 1 d = 1 7⇒ a + 8 d = 1 7 . . . . . . ( ii )Subtracting (i) from (ii) we get;a + 8 d - a - 6 d = 1 7 - 1 9 ⇒ 2 d = 9 - 7 63 ⇒ 2 d = 2 63 ⇒ d = 1 63Putting the value of d in either of the above equation , we get;a + 6 × 1 63 = 1 9 ⇒ a + 2 21 = 1 9 ⇒ a = 1 9 - 2 21 ⇒ a = 7 - 6 63 = 1 63So 63rd term = a + 63 - 1 d = 1 63 + 62 × 1 63 = 1Therefore 63rd term of an A.P. is 1.

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Answer 2

Answer:

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