if the 18th term of an ap is zero then prove that the 58 term is double the 38 term
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a18 = 0
a+17d = 0
a = - 17d
a58 = a+ 57d
= - 17d+57d
= 40d
a38 = a+37d
= - 17d +37d
= 20d
a58/a38
40d/20d
= 2
Hence proved
Hope it helps
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a+17d = 0
a = - 17d
a58 = a+ 57d
= - 17d+57d
= 40d
a38 = a+37d
= - 17d +37d
= 20d
a58/a38
40d/20d
= 2
Hence proved
Hope it helps
Mark as the BRAINLIEST
rajnambiar:
what is a
a is term of AP
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