Question

I want to know the answer of it... Urgently

Answer 1

Hi ,

From the figure ,

a ) In ∆ PQR ,

QR = 50m

Let PQ = x m


tan 60° = QR / PQ

√3 = 50 / x

x = 50/√3 ----( 1 )

b ) In ∆ TPQ ,

PQ = x = 50/√3 ,

Let PT = h m,

tan 30° = PT/ PQ

1/√3 = h / x

( 1/√3 ) x = h

h = ( 1/√3 ) ( 50/√3 )

= 50 / 3

h ≈ 16.67 m

I hope this helps you.

: )