if the 1st term of an H.P. is 'a' and the 2nd term is b;
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then what
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For the A.P., 1st term =p, nth term =q
q=p+(n−1)d, where d is the common difference
⇒d= (n−1q−p
(r−1)th term of the A.P. =p+
(n−1)r(q−p) = (n−1)p(n−1)+r(q−p) ...(1)
For H.P. 1st term =p, nth term =q
⇒ the corresponding A.P. has the first term p1
and the nth term q1
q1 = p1 +(n+1)D,
whre D is the common difference
⇒D= (n−1)q1 − p1 = pq(n−1)(p−q)(n−r)th
term of the corresponding A.P.
= p1 + pq(n−1) (n−r−1)(p−q) = pq(n−1)
q(n−1)+(n−r−1)(p−q)=
pq(n−1)(n−r−1)p+q =
pq(n−1)
p(n−1)+r(q−p)
Therefore. The (n−rth term of the H.P. =
p(n−1)+r(q−p)
pq(n−1).(2)
From (1) and (2) we see that the product of the terms =pq independent of r
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