Question

if the 2nd term of an AP is 13 and the 5th term is 25, what is it 17th term
30
33
37
38​

Answer 1

Answer:

a2 = 13,a5 = 25

a+d = 13 — 1 , a+4d = 25

using elimination method

a+ d = 13

a+ 4d = 25

‐ - -

——————–

-3d = -12

d = 4

put value of d in 1

a + 4 = 13

a = 13-4

a = 9

a17 = a + 16d = 9+ 16(4) = 73

Answer 2

Answer:

73

Step-by-step explanation:

given t2=13,t5=25

tn=a+(n-1)d where a is first term and d is difference

t2=a+(2-1)d

13=a+d

t5=a+(5-1)d

25=a+4d

sub t2 from t5

25-13=a+4d-4-d

12=3d

12/3=d

4=d

substitute d in t2

13=a+4

13-4=a

9=a

17th term is t17=a+(17-1)d

=9+(16)4

=9+64

=73