Question

If the 3 sides of a triangle are a ,root 3a, 2a,, then find the measure of angle opposite to the longest side? PLZ GIVE AN DETAILED ANSWER PLZ

Answer 1

Given a=a ,b=√3a c=2a

Here 2a> √3a> a .

By cosine rule we have

CosC=a²+b²-c²/2ab

CosC=a²+(√3a)²-(2a)²/2(a)(√3a)

= a²+3a²-4a²/2√3a²

=0

CosC= 0

Cos90°= CosC .

The angle opposite to the longest side is the longest angle.

Here pythagoras theorem is valid ,so it is a right angled triangle. Obviously 90° is the greatest angle

Answer 2

Answer:

Step-by-step explanation:

(√3a)²=(√2a)²+a²

3a²=2a²+a²

3a²=3a²

by converse of pythagoras theorem √3s is the hypotenuse

the angle opp to the hyp is 90*