If the 3rd and 6th term of A.P are 7 and13 . Find 1st ,difference and A.P
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a3 = a + 2d = 7
a6 = a + 5d = 13
a6 - a3 = 5d - 2d = 13 - 7
3d = 6
d = 2
Substituting in a3,
a + 2×2 = 7
a = 7 - 4 = 3
a2 = a + d = 3 + 2 = 5
AP = a1, a2, a3..... = 3, 5, 7......
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